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SSC Sample Paper Mock Test-14 SSC CGL Tear-II Paper-1

  • question_answer
    A tap can empty a tank in 1 h. A second tap can empty it in 30 min. If both the taps operate simultaneously, how much time is needed to empty the tank?

    A) 20 min

    B)  30 min

    C)  40 min

    D)  45 min

    Correct Answer: A

    Solution :

    1 h = 60min Rate of emptying the tank by the two taps are \[\frac{1}{60}\]and \[\frac{1}{30}\]of the tank per minute respectively. Rate of emptying the tank when both operate simultaneously\[=\frac{1}{60}+\frac{1}{30}=\frac{1+2}{60}=\frac{3}{60}=\frac{1}{20}\]of the tank per minute. \[\therefore \] Time taken by the two taps together to empty the tank = 20 min


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