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SSC Sample Paper Mock Test-14 SSC CGL Tear-II Paper-1

  • question_answer
    If a : b = c : d = e : f = 1 : 2, then (pa + qc + re) : (pb + qd + rf) is equal to

    A) p : (q + r)

    B)  (p + q) : r

    C)  2 : 3    

    D)  1 : 2

    Correct Answer: D

    Solution :

    \[\frac{a}{b}=\frac{c}{d}=\frac{e}{f}=\frac{1}{2}\]\[\Rightarrow \]\[\frac{pa}{pb}=\frac{qc}{qd}=\frac{re}{rf}=\frac{1}{2}\] \[\Rightarrow \]\[\frac{pa+qc+re}{pb+qd+rf}=\frac{1}{2}\]


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