A) Rs. 1352
B) Rs. 1377
C) Rs. 1275
D) Rs. 1283
Correct Answer: A
Solution :
| A = Rs. 2550 |
| R = 4% per annum |
| n = 2 yr |
| Let each of the two equal instalments be Rs. x. |
| Present worth \[=\frac{\text{Instalment}}{{{\left( \text{1+}\frac{\text{r}}{\text{100}} \right)}^{\text{n}}}}\] |
| \[{{P}_{1}}=\frac{x}{{{\left( 1+\frac{4}{100} \right)}^{1}}}=\frac{x}{1+\frac{1}{25}}=\frac{x}{\frac{26}{25}}\]\[\Rightarrow \]\[{{P}_{1}}=\frac{25}{26}x\] |
| Similarly, \[{{P}_{2}}={{\left( \frac{25}{26} \right)}^{2}}x=\frac{625}{676}x\] |
| \[{{P}_{1}}+{{P}_{2}}=A\] |
| \[\therefore \] \[\frac{25}{26}x+\frac{625}{676}x=2550\] |
| \[\Rightarrow \]\[\frac{(650+625)}{676}=2550\Rightarrow \frac{1275}{676}x=2550\] |
| \[\Rightarrow \] \[x=\frac{2550\times 676}{1275}\] |
| \[\therefore \] \[x=\] Rs. 1352 |
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