A) n
B) \[\frac{1}{n}\]
C) \[n\,\,(n-1)\]
D) None of these
Correct Answer: B
Solution :
\[\left\{ 1-\frac{1}{2} \right\}\times \left\{ 1-\frac{1}{3} \right\}\times \left\{ 1-\frac{1}{4} \right\}\times ...\times \left\{ 1-\frac{1}{n} \right\}\] \[=\frac{1}{2}\times \frac{2}{3}\times \frac{3}{4}\times ...\times \frac{n-2}{n-1}\times \frac{n-1}{n}=\frac{1}{n}\]
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