A) 100
B) 60
C) 75
D) None of these
Correct Answer: C
Solution :
| Scheduled time to complete the work = 40 days |
| 25 men in 24 days do \[\frac{1}{3}\]work |
| \[\therefore \]1 man in 1 day does \[=\frac{1}{3\times 25\times 24}=\frac{1}{1800}\]work |
| Work remaining \[=1-\frac{1}{3}=\frac{2}{3}\] |
| The work is to be completed 4 days before schedule i.e., in \[(40-4)=36\] days |
| Number of days left for\[\frac{2}{3}\text{rd}\]work \[=36-24=12\]days\[\frac{1}{1800}\]work is done in 1 day by 1 man |
| \[\therefore \]\[\frac{2}{3}\]work will be done in 12 days by |
| \[=1800\times \frac{2}{3}\times \frac{1}{12}=100\,\,\text{men}\] |
| 25 men are already working |
| \[\therefore \]Extra men to be employed\[=100-25=75\]men |
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