A) 0
B) 2
C) 4
D) 5
Correct Answer: D
Solution :
\[{{(a+b+c)}^{2}}={{a}^{2}}+{{b}^{2}}+{{c}^{2}}+2\,\,(ab+bc+ca)\] \[{{(6)}^{2}}=26+2\,\,(ab+bc+ca)\] \[2\,\,(ab+bc+ca)=10\] \[ab+bc+ca=\frac{10}{2}\] \[ab+bc+ca=5\]You need to login to perform this action.
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