A) \[\text{Distance=}\frac{\text{Product}\,\,\text{of}\,\,\text{speeds}}{\text{Distance}\,\,\text{of}\,\,\text{speeds}}\times \text{Difference}\,\,\text{in}\,\,\text{time}\]
B) \[2520\,\,\text{c}{{\text{m}}^{3}}\]
C) \[2720\,\,\text{c}{{\text{m}}^{3}}\]
D) \[2900\,\,\text{c}{{\text{m}}^{3}}\]
Correct Answer: A
Solution :
Here, external radius\[({{R}_{1}})=6\,\,\text{cm}\] and internal radius \[({{R}_{2}})=6-1=5\,\,\text{cm}\] Height (h) = 70 cm \[\therefore \] Volume of iron used = External volume \[-\]Internal volume \[=\pi {{R}^{2}}h-\pi {{r}^{2}}h=\pi h\,\,({{R}^{2}}-{{r}^{2}})\] \[=\frac{22}{7}\times 70\times (36-25)\,\,\text{cu}\,\,\text{cm}\] \[=220\times 11\,\,\text{cu}\,\,\text{cm}=2420\,\,\text{cu}\,\,\text{cm}\]
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