SSC Sample Paper Mock Test-10 SSC CGL Tear-II Paper-1

  • question_answer
    The sum of the squares of three consecutive natural numbers is 2030. Then, what is the middle number?

    A)  25

    B)  26

    C)  27

    D)  28

    Correct Answer: A

    Solution :

    Let the three consecutive natural numbers be x, \[x+1\] and \[x+2\]
    According to question,
    \[{{x}^{2}}+{{(x+1)}^{2}}+{{(x+2)}^{2}}=2030\]
    \[\Rightarrow \]\[{{x}^{2}}+{{x}^{2}}+2x+1+{{x}^{2}}+4x+4=2030\]
    \[\Rightarrow \]   \[3{{x}^{2}}+6x+5=2030\]
    \[\Rightarrow \]   \[3{{x}^{2}}+6x-2025=0\]
    \[\Rightarrow \]   \[{{x}^{2}}+2x-675=0\]
    \[\Rightarrow \]   \[{{x}^{2}}+27x-25x-675=0\]
    \[\Rightarrow \]   \[x\,\,(x+27)-25\,\,(x+27)=0\]
    \[\Rightarrow \]   \[(x-25)-25\,\,(x+27)=0\]
    \[\therefore \] \[x=25\] and \[-\,\,27\]


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