A) \[\frac{1}{3}\]
B) \[-\,\,\frac{1}{3}\]
C) \[-\,\,1\]
D) \[\frac{1}{2}\]
Correct Answer: A
Solution :
\[?={{[1-2\,\,{{(1-2)}^{-1}}]}^{-1}}\] \[=\frac{1}{[1-2\,\,{{(1-2)}^{-1}}]}=\frac{1}{\left[ 1-2\times \frac{1}{(1-2)} \right]}=\frac{1}{1+\frac{2}{1}}=\frac{1}{3}\]
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