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SSC Sample Paper Mock Test-10 SSC CGL Tear-II Paper-1

  • question_answer
    A and B starts at the same time with speeds of 40 km/h and 50 km/h respectively. If in covering the journey A takes 15 min longer than B, the total distance of the journey is

    A)  46 km

    B)  48 km

    C)  50 km

    D)  52 km

    Correct Answer: C

    Solution :

    Let the distance be x km.
    Time taken by \[A=\frac{x}{40}\text{h}\]
    Time taken by \[B=\frac{x}{50}\text{h}\]
    Now, \[\frac{x}{40}-\frac{x}{50}=\frac{15}{60}=\frac{5x-4x}{200}=\frac{15}{60}\]
    \[\therefore \]      \[x=\frac{15}{60}\times 200=50\,\,\text{km}\]
    \[\text{Distance=}\frac{\text{Product}\,\,\text{of}\,\,\text{speeds}}{\text{Distance}\,\,\text{of}\,\,\text{speeds}}\times \text{Difference}\,\,\text{in}\,\,\text{time}\]           \[=\frac{40\times 50}{50-40}\times \frac{15}{60}=50\,\,\text{km}\]


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