A) \[1+\frac{1}{x+4}\]
B) \[x+4\]
C) \[\frac{1}{x}\]
D) \[\frac{x+4}{x}\]
Correct Answer: D
Solution :
Given expression \[=\left( 1+\frac{1}{x} \right)\left( 1+\frac{1}{x+1} \right)\left( 1+\frac{1}{x+2} \right)\left( 1+\frac{1}{x+3} \right)\] \[=\frac{x+1}{x}\times \frac{x+2}{x+1}\times \frac{x+3}{x+2}\times \frac{x+4}{x+2}=\frac{x+4}{x}\]
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