A) Decrease approximately by 20%
B) Increase approximately by 2%
C) Increase approximately by 20%
D) Decrease approximately by 2%
Correct Answer: D
Solution :
Suppose strength of school in 1997 =100 Strength in 1998 after 10% increase \[=100\times \frac{100+10}{100}=110\] In 1999, 10% decrease \[=110\times \frac{100-10}{100}=99\] In 2000, 10% increases \[=99\times \frac{100+10}{100}=108.9\] In 2001, 10% decrease \[=108.9\times \frac{100-10}{100}=98.01\] Per cent decrease \[=100-98.01=\frac{1.99}{100}\times 100\] \[=1.99%=2%\]You need to login to perform this action.
You will be redirected in
3 sec