A) \[44\,\,{{m}^{2}}\]
B) \[33\,\,{{m}^{2}}\]
C) \[66\,\,{{m}^{2}}\]
D) \[88\,\,{{m}^{2}}\]
Correct Answer: A
Solution :
[a] Radius (r) of garden roller \[=\frac{1.4}{2}=0.7\,m.\] Height (h) of garden roller = 2 m \[\therefore \] Area covered in 1 revolution \[=2\pi rh,\] (Surface Area) \[=2\times \pi \times 0.7\times 2=8.8\,{{m}^{2}}\] \[\therefore \] Area covered in 5 revolutions \[=8.8\times 5\] \[=44.0\,{{m}^{2}}\]
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