question_answer

If the lines \[\frac{x-a+d}{\alpha -\delta }=\frac{y-a}{\alpha }=\frac{z-a-d}{\alpha +\delta }\]  and \[\frac{x-b+c}{\beta -\gamma }=\frac{y-b}{\beta }=\frac{z-b-c}{\beta +\gamma }\] are coplanar, then equation to the plane in which they lie, is

A)  \[x+y+z=0\]               

B)  \[x-y+z=0\]

C)  \[x-2y+z=0\]

D)  \[x+y-2z=0\]

E)  None of these