question_answer

PQR is a triangle, right angled at P. If PQ = 10 cm and PR = 24 cm. Find QR.

Answer:

Given, \[\Delta PQR\]is right angled at P, in which PQ = 10 cm and PR = 24 cm In,\[\Delta PQR\] by using Pythagoras theorem, \[Q{{R}^{2}}=P{{Q}^{2}}+P{{R}^{2}}\Rightarrow Q{{R}^{2}}={{\left( 10 \right)}^{2}}+{{\left( 24 \right)}^{2}}\] \[Q{{R}^{2}}=100+576\Rightarrow Q{{R}^{2}}=676\] \[QR=\sqrt{676}=26\]                                                                                                                                                                      Hence, the length of QR is 26 cm.