6th Class Mathematics Sample Paper Mathematics Sample Paper-9

  • question_answer
    How will you construct a \[45{}^\circ \] angle?

    Answer:

    To construct an angle of \[45{}^\circ \], steps of construction are given below:
    Step I: Draw a ray OA and take O as centre and with any convenient radius, draw an arc which cuts OA at P.                          
    Step II: Without disturbing the radius on the compasses, draw an arc with P as centre which cuts the first arc at Q.                                        
    Step III: Again, draw an arc R with Q as centre and with same radius which intersects the arc drawn in Step 1 at P.        
    Step IV: Take Q and R as centre and with radius more than half of length RQ. draw two arcs respectively which intersects each other at B.                                                                                                                           
    Step V: Join OB which intersects QR at I and produce up to C. Then, \[\angle AOC=90{}^\circ \].     
    Step VI: Now, take P and I as a centre and with radius more than half of length PI, draw two arcs respectively which intersect each other at D.                    
    Step VII: Join OD.
    Then, \[\angle AOD\]is the required angle of \[45{}^\circ \].


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