Answer:
Let ABCD be a rectangle such that AB = 40 cm and AC = 41 cm. In right angled ∆ABC, right angled at B, by Pythagoras theorem, we have \[B{{C}^{2}}=A{{C}^{2}}A{{B}^{2}}\] \[={{41}^{2}}{{40}^{2}}\] = (41 + 40) (41 ? 40) = 81 × 1 = 81 BC = 81 = 9 cm, Now, perimeter of rectangle = 2(AB + BC) = 2 (40 + 9) cm = 2 × 49 cm = 98 cm 1
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