Answer:
Volume of cylinder B is greater because it contains more thickness in comparison to A. For cylinder B, r = 7 cm, h = 7 cm Volume of cylinder \[B=\pi {{r}^{2}}h\] \[=\frac{22}{7}\times 7\times 7\times 7\] =1078 cm3. Surface area of cylinder \[B\text{ }=\text{ }2\pi rh\] \[=2\times \frac{22}{7}\times 7\times 7\] For cylinder A, =308 cm2 radius of cylinder A = 3.5 cm, /i = 14 cm Volume \[A=\pi {{r}^{2}}h\] \[=\frac{22}{7}\times {{(3.5)}^{2}}\times 14\] \[=539c{{m}^{2}}\] Surface area of cylinder \[A=2\pi rh\] \[=2\times \frac{22}{7}\times 3.5\times 14\] = 308 \[c{{m}^{2}}\] Volume of cylinder B > volume of cylinder A. Surface area of both cylinders are same.
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