Answer:
Quadrilateral is divided into triangle. Here, \[{{h}_{1}}=13\text{ }m,\text{ }{{h}_{2}}=8\text{ }m\] and AC = 24 m Area of quadrilateral ABCD = Area of \[\Delta ADC\]+ Area of \[\Delta ABC\] \[=\frac{1}{2}\times b\times {{h}_{1}}+\frac{1}{2}\times b\times {{h}_{2}}\] \[=\frac{1}{2}\times 24\times 13+\frac{1}{2}\times 24\times 8\] \[=12\times 13+12\times 8\] = 156 + 96 \[=\text{ }252\text{ }{{m}^{2}}\] The area of quadrilateral field\[=\text{ }252\text{ }{{m}^{2}}\].
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