7th Class Mathematics Sample Paper Mathematics Sample Paper - 4

  • question_answer
    Simplify the following:
    (a) \[{{({{6}^{-1}}-{{8}^{-1}})}^{-1}}+{{({{2}^{-1}}-{{3}^{-1}})}^{-1}}\]
    (b) \[{{\left\{ {{6}^{-1}}+{{\left( \frac{3}{2} \right)}^{-1}} \right\}}^{-1}}\]
     

    Answer:

    (a) \[\left( {{6}^{-1}}-{{8}^{-1}} \right)+\left( {{2}^{-1}}+{{3}^{-1}} \right)\]
      \[={{\left( \frac{1}{6}-\frac{1}{8} \right)}^{-1}}+{{\left( \frac{1}{2}-\frac{1}{3} \right)}^{-1}}\]
      \[={{\left( \frac{4-3}{24} \right)}^{-1}}+{{\left( \frac{3-2}{6} \right)}^{-1}}\]
      \[={{\left( \frac{1}{24} \right)}^{-1}}+{{\left( \frac{1}{6} \right)}^{-1}}\]
      = 24 + 6 = 30                                                                                                                        
    (b) \[{{\left\{ {{6}^{-1}}+\left( {{\frac{3}{2}}^{-1}} \right) \right\}}^{-1}}={{\left( \frac{1}{6}+\frac{2}{3} \right)}^{-1}}\]
      \[={{\left( \frac{1+4}{6} \right)}^{-1}}=\left( \frac{5}{6} \right)\]
      \[=\frac{6}{5}\]          


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