Answer:
Here, a volleyball court and a swimming pool both are in rectangular shape and their dimensions are directly proportional. Let I and b are length and breadth, respectively. If I = b \[\Rightarrow \] \[\frac{{{l}_{1}}}{{{b}_{1}}}=\frac{{{l}_{2}}}{{{b}_{2}}}\] Here,\[{{l}_{1}}=18m,\,{{b}_{1}}=9m,\,{{l}_{2}}=75m,{{b}_{2}}=?\] Then, \[\frac{18}{9}=\frac{75}{{{b}_{2}}}\] \[2{{b}_{2}}=75\] \[{{b}_{2}}=\frac{75}{2}\] \[{{b}_{2}}=37.5m\] So, the width of the pool is 37.5 m.
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