6th Class Mathematics Sample Paper Mathematics Sample Paper-3

  • question_answer
    Give a proper fraction:
    (a) Whose numerator is 5 and denominator is 7.
    (b) Whose denominator is 9 and numerator is 5.
    (c) Whose numerator and denominator add up to 10. How many fractions of this kind can you make?
    (d) Whose denominator is 4 more than the numerator. Give any five. How many more can you make?


    (a)        Numerator = 5, Denominator = 7
    So, the fraction \[=\frac{5}{7}\]                                                                                                                                                  
    (b)        Numerator = 5, Denominator = 9
    So, the fraction \[=\frac{5}{9}\]                                                                                                                                                 
    (c) Possible   pairs   of   numerator   and denominator which add up to 10 are 0, 10; 1, 9; 2, 8; 3, 7; 4, 6 which give us proper fractions: \[\frac{0}{10},\frac{1}{9},\frac{2}{8},\frac{3}{7},\frac{4}{6}\]  These are 5 in number.                                                                          
    (d) 5 proper fractions in which denominator is 4 more than the numerator are  \[\frac{0}{4},\frac{1}{5},\frac{2}{6},\frac{3}{7},\frac{5}{9}\]
    We can make an infinite number of proper fractions according to the given conditions.         

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