• # question_answer Give a proper fraction: (a) Whose numerator is 5 and denominator is 7. (b) Whose denominator is 9 and numerator is 5. (c) Whose numerator and denominator add up to 10. How many fractions of this kind can you make? (d) Whose denominator is 4 more than the numerator. Give any five. How many more can you make?

 (a)        Numerator = 5, Denominator = 7 So, the fraction $=\frac{5}{7}$ (b)        Numerator = 5, Denominator = 9 So, the fraction $=\frac{5}{9}$ (c) Possible   pairs   of   numerator   and denominator which add up to 10 are 0, 10; 1, 9; 2, 8; 3, 7; 4, 6 which give us proper fractions: $\frac{0}{10},\frac{1}{9},\frac{2}{8},\frac{3}{7},\frac{4}{6}$  These are 5 in number. (d) 5 proper fractions in which denominator is 4 more than the numerator are  $\frac{0}{4},\frac{1}{5},\frac{2}{6},\frac{3}{7},\frac{5}{9}$ We can make an infinite number of proper fractions according to the given conditions.