• # question_answer A number is increased by 20% and then it is decreased by 20%. Find the net increase or decrease per cent.

 Let the number be 100 Increase in the number = 20% of 100 =20 So,       increased number = 100 + 20 = 120 Decrease in the number = 20% of 120 $=\frac{20}{100}\times 120=24$ So,  new number $=\text{ }120\text{ }-\text{ }24\text{ }=\text{ }96$ Net  decrease $=\text{ }100\text{ }-\text{ }96\text{ }=\text{ }4$ Hence,   net decrease per cent $=\frac{4}{100}\times 100=4%$