(a) \[18+11x+{{x}^{2}}\] |
(b) \[{{y}^{2}}-2y-15\] |
Answer:
(a) \[18+\text{11}x+{{x}^{2}}=\text{ }{{x}^{2}}+1\text{1}x+18\] \[={{x}^{2}}+\left( 9+2 \right)\text{ }x+18\] \[={{x}^{2}}+9x+2x+18\] \[=x(x+9)+2(x+9)\] = (x + 9) (x + 2) (b) \[{{y}^{2}}-2y-15={{y}^{2}}-(5-3)y-15\] \[={{y}^{2}}-5y+3y-15~\] \[=y\left( y-5 \right)+3\left( y-5 \right)\] \[=\left( y-5 \right)\left( y+3 \right)\]
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