Answer:
Let the length and breadth of the plot be 11 x and 4x, respectively. \[\therefore \]\[Perimeter\text{ }of\text{ }the\text{ }plot\text{ }=\text{ }\frac{Total\text{ }cost}{Cost\text{ }of\text{ }1\text{ }meter}\] \[=\frac{75000}{100}=750m\] We know that perimeter of rectangle = 2 (l + b) \[\therefore \] According to question, \[2\left( 11x+4x \right)=750\] or, \[15x=\frac{750}{2}\] or, \[15x=375\] or, \[x=\frac{375}{15}\] or, x = 25 Hence, length of plot \[=11\times 25=275\text{ }m\] and breadth of the plot \[4\times 25=100\text{ }m.\]
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