Answer:
Area of trapezium AEHD =\[\frac{1}{2}\times h\times \] (sum of parallel sides) \[=\frac{1}{2}\times 4\times (28+20)\] \[=2\times 48=96\,\,c{{m}^{2}}\] Area of trapezium DHGC =\[\frac{1}{2}\times h\times \] (sum of parallel sides) \[=\frac{1}{2}\times 4\times (24+16)\] \[=2\times 40=80\,\,c{{m}^{2}}\] Area of trapezium BFGC =\[\frac{1}{2}\times h\times \] (sum of parallel sides) \[=\frac{1}{2}\times 4\times (28+20)\] \[=2\times 48=96\,c{{m}^{2}}\] Area of trapezium AEFB =\[\frac{1}{2}\times h\times \](sum of parallel sides) \[=\frac{1}{2}\times 4\times (24+16)\] \[=\text{ }2\times 40=80\text{ }c{{m}^{2}}\]
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