Answer:
Let shirt material be 3x and trouser material be 2x metres. The cost of shirt material \[=50\times 3x=150x\] The selling price at 12% profit \[=\frac{100+12}{100}\times 150x\] \[=\frac{112}{100}\times 150x\] = 168 x The cost of trouser material \[=90\times 2x=180x\] The selling price at 10% profit \[=\frac{100+10}{100}\times 180x\] \[=\frac{110}{100}\times 180x=198x\] According to question, \[168x+\text{ }198x=36,600\] or, \[366x=\text{ }36,600\] or, \[x=\frac{36600}{366}\] or, x = 100 \[\therefore \] Trouser material \[=\text{ }2\times 100=200\text{ }m\] Hence, Hasan bought 200 m trouser material.
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