Answer:
Given, length of a rectangular field = 8 m Breadth of a rectangular field = 2 m Now, perimeter of rectangular \[=2\times (length+Breadth)\] \[=2\times (8+2)=2\times 10\] \[=20\,m\] \[\therefore \] Area of rectangular field = length \[\times \] breadth \[=8\times 2=16\text{ }{{m}^{2}}\] According to the question. Perimeter of square = perimeter of rectangular field \[\Rightarrow \] \[4\times side=20\] \[\Rightarrow \] \[\frac{4\times side}{4}=\frac{20}{4}\] [Dividing both sides by 4] side = 5m Now, area of square \[=side~\times side\] \[=5\times 5=25\text{ }{{m}^{2}}\] Hence, the area of square field is greater than the area of rectangular field.
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