Answer:
Volume, \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{1}{64}\] \[\frac{a_{1}^{3}}{a_{2}^{3}}=\frac{1}{64}\] \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{1}{4}\] Area of first face for first cube \[={{a}_{1}}\times {{a}_{1}}\] \[=1\times 1\] Area of first face of other cube \[={{a}_{2}}\times {{a}_{2}}\] = 4 × 4 Ratio will be \[=\frac{1}{16}\]
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