A) \[P(A)=\frac{1}{4}\]
B) \[P(B)=\frac{1}{5}\]
C) \[P(A)=\frac{1}{3}\]
D) \[P(B)=\frac{2}{3}\]
Correct Answer: A
Solution :
[a] \[S=\left\{ H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6 \right\}\] \[n\left( S \right)=12\] \[A=\left\{ H2,H4,H6 \right\}\] \[B=\left\{ T3,T6 \right\}\] \[\Rightarrow n\left( A \right)=3\] \[n\left( B \right)=2\] \[\therefore P(A)=\frac{3}{12}=\frac{1}{4}\] \[P(B)=\frac{2}{12}=\frac{1}{6}\] Hence, option [a] is correct.You need to login to perform this action.
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