A) 6
B) 5
C) 4
D) 1
Correct Answer: A
Solution :
[a] \[\because x={{t}^{2}}-3t+5\] \[y=2{{t}^{2}}-2t+6\] Now, slope of the tangent \[\frac{dy}{dx}=\frac{\frac{dy}{dt}}{\frac{dx}{dt}}=\frac{2.2.t-2}{2.t-3}=\frac{4t-2}{2.t-3}\] \[\therefore {{\left( \frac{dy}{dx} \right)}_{at\,t=2}}=\frac{8-2}{4-3}=6\] Hence, option [a] is correct.You need to login to perform this action.
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