A) \[\frac{1}{2}In{{\left( \frac{x-1}{x+1} \right)}^{2}}+C\]
B) \[\frac{1}{2}In{{\left( \frac{x+1}{x-1} \right)}^{2}}+C\]
C) \[\frac{1}{4}\left[ In{{\left( \frac{x-1}{x+1} \right)}^{2}} \right]+C\]
D) \[\frac{1}{4}\left[ In\left( \frac{x+1}{x-1} \right) \right]+C\]
Correct Answer: C
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