A) \[2x=3\]
B) \[~x=3\]
C) \[3x=2\]
D) \[x=-3\]
Correct Answer: A
Solution :
[a] Given equation of the parabola be \[{{y}^{2}}+4y+4x+2=0\] \[{{y}^{2}}+2.2y+4-4+4x+2=0\] \[{{(y+2)}^{2}}=-4\left( x-\frac{1}{2} \right)Let\,{{y}^{2}}=-4.x\] When \[{{y}^{2}}=-4a\text{ }X\] then equation of the directrix be \[X=a,here\text{ }a=1\text{ }and\text{ }X=x-\frac{1}{2}~\] \[\therefore x-\frac{1}{2}~=1\] \[x=1+\frac{1}{2}=\frac{3}{2}\Rightarrow 2x=3\]You need to login to perform this action.
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