question_answer

If  \[{{x}^{2}}+x+1\]is a factor of\[a{{x}^{3}}+b{{x}^{2}}+cx+d\], then the real root of \[a{{x}^{3}}+b{{x}^{2}}+cx+d=0\]

A)  \[-\frac{d}{a}\]          

B)  \[\frac{d}{a}\]            

C)  \[\frac{a}{d}\]             

D)  \[\frac{c}{d}\]