A) circle
B) a parabola
C) an ellipse
D) hyperbola
Correct Answer: B
Solution :
| Here, \[\sqrt{ax}+\sqrt{by}=1\] |
| Squaring both sides, \[ax+by+2\sqrt{abxy}=1\] |
| Or \[2\sqrt{abxy}=(1-ax-by)\] again squaring \[4abxy=1+{{a}^{2}}{{x}^{2}}+{{b}^{2}}{{x}^{2}}+{{b}^{2}}{{y}^{2}}-2ax-2by+2abxy\]\[{{a}^{2}}{{x}^{2}}+{{b}^{2}}{{y}^{2}}-2abxy-2ax-2by+1=0\] |
| which is clearly as parabola. \[({{H}^{2}}-AB=0;\,\,\,\Delta \ne 0)\] |
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