A) less than \[{{q}^{2}}\,(7p-12)\]
B) greater than \[{{q}^{2}}\,(7p-12)\]
C) less than \[{{q}^{2}}\,(12p-7)\]
D) greater than \[{{q}^{2}}\,(12p-7)\]
Correct Answer: A
Solution :
| \[3<p<4\] |
| \[\Rightarrow \]\[{{p}^{2}}-7p+12<0\] and \[q>4\]or \[q<3\] |
| \[\Rightarrow \]\[{{q}^{2}}-7q+12>0\] |
| \[\therefore \]\[{{p}^{2}}\,(7q-12)<{{q}^{2}}(7p-12)\] |
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