| If force constant of spring is \[k=\frac{2mg}{\ell }\] and now mass m is displaced down ward from equilibrium and released. Then time period will be- |
 |
A) \[2\pi \sqrt{\frac{\ell }{2g}}\]
B) \[2\pi \sqrt{\frac{\ell }{g}}\]
C) \[\frac{4\pi }{3}\sqrt{\frac{\ell }{2g}}+\sqrt{\frac{6\ell }{g}}\]
D) \[\pi \sqrt{\frac{\ell }{2g}}+\sqrt{\frac{8\ell }{g}}\]
Correct Answer: A
Solution :
For spring block system \[T=2\pi \sqrt{\frac{m}{k}}=2\pi \sqrt{\frac{m}{2mg}}=2\pi \sqrt{\frac{\ell }{2g}}\]
You need to login to perform this action.
You will be redirected in
3 sec
