KVPY Sample Paper KVPY Stream-SX Model Paper-30

  • question_answer
    In the diagram shown, the charge +Q is fixed. Another charge +2q, is projected from a distance R from the fixed charge. Minimum separation between the two charges if the velocity becomes \[\frac{1}{\sqrt{3}}\] times of the projected velocity, at this moment is (Assume gravity to be absent) -

    A) \[\frac{\sqrt{3}}{2}R\]

    B) \[\sqrt{3}\,R\] 

    C) \[\frac{1}{2}R\]

    D) \[4R\]

    Correct Answer: A

    Solution :

    Force F acting on +2q passes through Q so \[\tau \] of force F about Q = 0
    Angular momentum about Q remain conserved
    \[{{L}_{i}}={{L}_{f}}\]
    \[mVR\,\,\sin 30{}^\circ =m{{V}_{1}}d\]
    \[\frac{mVR}{2}=\frac{mVd}{\sqrt{3}}\]
    \[d=\frac{\sqrt{3}R}{2}\]


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