| In view of the signs of \[{{\Delta }_{r}}G{}^\circ \]for the following reaction: |
| \[Pb{{O}_{2}}+Pb\to 2PbO,{{\Delta }_{r}}G{}^\circ <0\] |
| \[Sn{{O}_{2}}+Sn\to 2SnO,{{\Delta }_{r}}G{}^\circ <0\] |
| Which oxidation states are more characteristics for lead and tin? |
A) For lead +2, for tin +2
B) For lead +4, for tin +4
C) For lead +2, for tin +4
D) For lead +4, for tin+2
Correct Answer: C
Solution :
[c] negative \[{{\Delta }_{r}}G{}^\circ \] value indicated that +2 oxidation state is more stable for \[P{{b}^{2+}}\] Also it is supported by inert pair effect that +2 oxidation state is more stable for Pb and +4 oxidation state is more stable for sn. i.e., \[S{{n}^{2+}}<P{{b}^{2+}},S{{n}^{4+}}>P{{b}^{4+}}\]
You need to login to perform this action.
You will be redirected in
3 sec
