A) \[\overset{*}{\mathop{\pi }}\,-orbital\]
B) \[\pi -orbital\]
C) \[\overset{*}{\mathop{\sigma }}\,-orbital\]
D) \[\sigma -orbital\]
Correct Answer: A
Solution :
| During change of \[{{O}_{2}}\] to ,the \[O_{2}^{-}\] the electronic configuration of \[{{O}_{2}}\] \[\left( total\,{{e}^{-}}=16 \right)\] |
| \[\sigma \left( 1{{s}^{2}} \right),\overset{*}{\mathop{\sigma }}\,\left( 1{{s}^{2}} \right),\sigma \left( 2{{s}^{2}} \right),\overset{*}{\mathop{\sigma }}\,(2{{s}^{2}}),\sigma \left( 2p_{z}^{2} \right)\] |
| \[\pi \left( 2p_{x}^{2} \right)\approx \left( 2p_{y}^{2} \right),\overset{*}{\mathop{\pi }}\,\left( 2p_{x}^{1} \right)\approx \overset{*}{\mathop{\pi }}\,\left( 2p_{y}^{1} \right)\] and configuration of \[O_{2}^{-}\] ,\[\left( total\,{{e}^{-}}=17 \right)\] |
| \[\sigma \left( 1{{s}^{2}} \right),\overset{*}{\mathop{\sigma }}\,\left( 1{{s}^{2}} \right),\sigma \left( 2{{s}^{2}} \right),\overset{*}{\mathop{\sigma }}\,(2{{s}^{2}}),\overset{*}{\mathop{\sigma }}\,\left( 2p_{z}^{2} \right),\pi \left( 2p_{x}^{2} \right)\] \[\approx \pi \left( 2p_{y}^{2} \right),\overset{*}{\mathop{\pi }}\,\left( 2p_{x}^{2} \right)\approx \overset{*}{\mathop{\pi }}\,\left( 2p_{y}^{1} \right)\] Thus, electron goes in the\[\overset{*}{\mathop{\pi }}\,\], -orbital. |
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