KVPY Sample Paper KVPY Stream-SX Model Paper-18

  • question_answer
    The equation \[\left( \cos p-1\, \right){{x}^{2}}+\left( \cos p \right)x\]+sin p=0 in the variable x, has real roots. Then p can take any value in the interval

    A) \[\left( 0,2\pi  \right)\]

    B) \[\left( -\pi ,0 \right)\]

    C) \[\left( -\frac{\pi }{2},\frac{\pi }{2} \right)\]

    D) \[\left( 0,\pi  \right)\]

    Correct Answer: D

    Solution :

    The given equation is \[\left( \cos \,p-1 \right){{x}^{2}}+\left( \cos \,p \right)x+\sin p=0\]
    For this equation to have real roots \[D\ge 0\]\[\Rightarrow {{\cos }^{2}}p-4\sin p\left( \cos p-1 \right)\ge 0\] 
    \[\Rightarrow {{\cos }^{2}}p-4\sin p\cos p+4{{\sin }^{2}}p+4\sin p-4{{\sin }^{2}}p\ge 0\]\[\Rightarrow {{\left( \cos p-2\sin p \right)}^{2}}+4\sin p\left( 1-\sin \,p \right)\ge 0\]
    For every real value of \[p{{\left( \cos p-2\sin p \right)}^{2}}\ge 0\]
    and \[1-\sin p\ge 0\therefore D\ge 0,\,\forall p\in \left( 0,\pi  \right)\]


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