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KVPY Sample Paper KVPY Stream-SX Model Paper-18

  • question_answer
    The recognition site of the enzyme \[TaqI\] is TCGA. What would be the maximum number of recognition sites that this enzyme would have on a DNA molecule that is 5kb long?

    A) 20

    B) 35

    C) 15

    D) 2

    Correct Answer: A

    Solution :

    The frequency of cutting DNA sequence in a random for a given restriction enzyme is once per every 4", where n is the number of bases in the restriction enzymes recognition sequence. The "4" derives from the fact that there are four different possible nucleotides that maybe inserted at anyone position (G, A, T, or C).
    \[Taq\]Has a four-base recognition site, so it will cut once per every 44 or 256 bases.
    Number of restriction sites \[=\frac{Number\,of\,based\,in\,DNA\,molecule\,}{\operatorname{Average}\,length\,of\,restriction\,fragment}\]
    \[=\frac{5000}{256}=19.5\approx 20\]   


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