A) 15 km
B) 28 km
C) 40 km
D) 12 km
Correct Answer: B
Solution :
Kinetic energy of a molecule at temperature T is \[KE=\frac{1}{2}mv_{rms}^{2}=\frac{3}{2}{{K}_{B}}T\] |
The molecule can rises until whole of its kinetic energy is changed to potential energy. |
Let this height is h. Then, \[mgh=\frac{3}{2}{{K}_{B}}T\] |
\[\Rightarrow \]\[h=\frac{3{{K}_{B}}T}{2mg}=\frac{3\times 1.38\times {{10}^{-\,23}}\times 300}{2\times 4.5\times {{10}^{-\,26}}\times 10}\] |
\[=27.6\,km\approx 28\,km\] |
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