A) +71.5 amp
B) 35.7 amp
C) 142.96 amp
D) 285.93 amp
Correct Answer: A
Solution :
\[2HSO_{4}^{-}\xrightarrow{{}}{{S}_{2}}O_{8}^{-\,-}+2{{H}^{+}}+2{{e}^{-}}\] |
so required rate\[~=1\,\,\text{mole}/hr\]\[=2\,\,\text{mole}\] of \[{{e}^{-}}/hr\] |
\[=\frac{2\times 96500\,\,C}{3600\,\,\sec }=\frac{2\times 965}{36}A\simeq 53.6\,\,A\] |
so required current \[=\frac{4}{3}\times 53.6\,A=71.4\,A\] |
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