\[v-t\]graph of a particle is |
Its distance-time graph is |
A)
B)
C)
D)
Correct Answer: D
Solution :
\[s(t)=\int_{0}^{t}{\left| {{v}_{x}} \right|dt=\frac{{{t}^{2}}}{2},0\le t\le 1}\] |
\[t-\frac{1}{2},1<t\le 3\] |
\[4t-\frac{{{t}^{2}}}{2}-5,3<t\le 4\] |
\[\frac{{{t}^{2}}}{2}-4t+11,4<t\le 6\] |
\[14t-{{t}^{2}}-43,6<t\le 7\] |
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