A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
Calculating the oxidation state of nitrogen in give molecules; |
Oxidation state of N in\[{{\operatorname{NH}}_{3}}\]is \[x+3\times \left( +1 \right)=0\,\operatorname{or}\,x=-3\] |
Oxidation state of N in \[{{\operatorname{NaNO}}_{3}}\] |
\[1+x+3\times \left( -2 \right)=0\operatorname{or}\,x=+5\] |
Oxidation state of N in \[{{\operatorname{NaN}}_{3}}\]\[+1+3x=0\,\operatorname{or}\,x=-\frac{1}{3}\] |
Oxidation state of N in\[{{\operatorname{mg}}_{3}}{{N}_{2}}\] is \[3\times 2+2x=0\,\operatorname{or}x=-3\] |
Thus 3 molecules (i.e.\[{{\operatorname{NH}}_{3}}\], \[{{\operatorname{NaN}}_{3}}\]and\[{{\operatorname{mg}}_{3}}{{N}_{2}}\]) have nitrogen in negative oxidation state. |
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