| Consider the following compound: | |
| [a]\[{{\operatorname{IF}}_{5}}\] | [b] \[{{\operatorname{CII}}^{-}}_{4}\] |
| [c] \[{{\operatorname{XeO}}_{2}}{{F}_{2}}\] | [d] \[{{\operatorname{NH}}^{-}}_{2}\] |
| [e] \[{{\operatorname{BCl}}_{3}}\] | [f] \[{{\operatorname{BeCl}}_{2}}\] |
| [g] \[\operatorname{B}{{\left( OH \right)}_{3}}\] | |
| If x, y and z are total number of compounds in Which central atom used their all three p-orbitals, Only two p-orbitals and only one p-orbital in Hybridisation respectively. Then value of"\[''x + y - z'' is\] | |
A) 5
B) 3
C) 4
D) 2
Correct Answer: A
Solution :
| (i) \[{{\operatorname{IF}}_{5}}\left( s{{p}^{3}}d \right)\] | (ii) \[\operatorname{CII}_{4}^{-}\left( s{{p}^{3}}{{d}^{2}} \right)\] |
| (iii) \[{{\operatorname{XeO}}_{2}}{{F}_{2}}\left( s{{p}^{3}}d \right)\] | (iv) \[\operatorname{NH}_{2}^{-}\left( s{{p}^{3}} \right)\] |
| (v) \[{{\operatorname{BCl}}_{3}}\left( s{{p}^{2}} \right)\] | (vi) \[BeC{{l}_{2}}\left( sp \right)\] |
| (vii) \[B{{\left( OH \right)}_{3}}\left( s{{p}^{2}} \right)\] | |
| \[x=4,y=2,z=1\] | |
| \[\therefore x+y-z=4+2-1=5\] | |
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