A) \[150ppm\]
B) \[300 ppm\]
C) \[450 ppm\]
D) \[600 ppm\]
Correct Answer: B
Solution :
\[\operatorname{Milliequivalent}\]of \[\operatorname{Ca}{{\left( HC{{O}_{3}} \right)}_{2}}\] |
\[\equiv Milliequivalent of\]\[{{\operatorname{CaCO}}_{3}}\] |
\[\equiv Milliequivalent of\,HCl\] |
Now, \[{{\operatorname{V}}_{1}}{{N}_{1}}={{V}_{2}}{{N}_{2}}\]\[1000\times \frac{\operatorname{w}}{100/2}=30\times \frac{1}{50}\Rightarrow \operatorname{w}=0.03g\] |
For 100mL the amount of \[{{\operatorname{CaCO}}_{3}}\]\[=0.03g=0.03g\times 1{{0}^{3}}\] |
For \[{{10}^{6}}\operatorname{mL}=\frac{0.03}{100}\times {{10}^{6}}=300\operatorname{ppm}\] |
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