JEE Main & Advanced Sample Paper JEE Main Sample Paper-9

  • question_answer
    If isotopic distribution of C -12 and C -14 is 98% and 2% respectively then the number of C-14 atoms in 12 g of carbon is

    A)  \[1.032\times {{10}^{22}}\]                        

    B) \[3.01\times {{10}^{22}}\]

    C)  \[5.88\times {{10}^{23}}\]                          

    D)  \[6.023\times {{10}^{23}}\]

    Correct Answer: A

    Solution :

    In 12 g carbon, mass of C-14 isotope \[=12\times \frac{2}{100}=0.24g\] \[\therefore \]Number of C -14 atoms in 12 g of \[C=\frac{0.24}{14}\times 6.02\times {{10}^{23}}\]\[=1.032\times {{10}^{22}}\]


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