| Statement-1: If the lengths of sub tangent and subnormal at point (x, y) on \[y=f(x)\] are respectively 9 and 4. Then \[x=\pm 6\] |
| Statement-2: Product of sub tangent and sub normal is square of the ordinate of the point. |
A) Statement-1 is false, Statement-2 is true
B) Statement-1 is true, Statement-2 is true, and Statement-2 is a correct explanation for Statement-1
C) Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.
D) Statement-1 is true, Statement-2 is false.
Correct Answer: A
Solution :
\[\left| \frac{{{y}_{l}}}{m} \right|=9\]and\[\left| {{y}_{l}}m \right|=4\] \[\Rightarrow \]\[{{\left| {{y}_{l}} \right|}^{2}}=36\]\[\Rightarrow \]\[{{y}_{1}}+\pm 6\] Product of sub tangent and sub normal is \[y_{1}^{2}.\] Statement 1 is false. Statement 2 is true.
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